let T denote a linear operator on a vector space V. suppose that every subspace of V is invariant under T. prove that T is a scalar multiple of the identity map.

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- Jan 7th 2009, 06:12 AMKat-Mhelp me on invariant subspace please
let T denote a linear operator on a vector space V. suppose that every subspace of V is invariant under T. prove that T is a scalar multiple of the identity map.

please help me. - Jan 7th 2009, 07:54 AMOpalg
Step 1: Let x be a nonzero vector in V. Then the one-dimensional subspace spanned by x is invariant under T. So , for some scalar that (possibly) depends on x.

Step 2: Let x and y be linearly independent vectors in V. Then . Deduce from this that . Thus the constant c is in fact the same for every vector, and hence T is c times the identity. - Jan 7th 2009, 08:57 AMKat-Mthanks
thank you very much. you really helped me.