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Math Help - Isomorphisms in Abstract Algebra

  1. #1
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    Isomorphisms in Abstract Algebra

    Prove that Q* under multiplication (the set of nonzero rational numbers) is not isomorphic to R* under multiplication (the set of nonzero real numbers).

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  2. #2
    Member
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    Dec 2008
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    Dear bluejay,

    of course not.
    measure (Q) = measure (N)
    but
    measure(R) is continuos.
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