Let G be a finite group and let H be a subgroup of G.

NH, the normalizer of H in G is defined to be the set {x|xHx^-1}

Prove that NH is a subgroup of G

Prove that |{xHx^-1|x in G}| = |G/NH|

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- Dec 9th 2008, 01:24 PMCoda202Normalizer of a Group
Let G be a finite group and let H be a subgroup of G.

NH, the normalizer of H in G is defined to be the set {x|xHx^-1}

Prove that NH is a subgroup of G

Prove that |{xHx^-1|x in G}| = |G/NH| - Dec 9th 2008, 04:51 PMThePerfectHacker
- Dec 10th 2008, 12:55 PMGammaalready answered for you
I already did this for you earlier in the week...

http://www.mathhelpforum.com/math-he...t-algebra.html