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Math Help - Basis

  1. #1
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    Basis

    U = span{(1 1 0), (0 1 1)}
    Find a basis for U(prep)
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  2. #2
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    Quote Originally Posted by ishan View Post
    U = span{(1 1 0), (0 1 1)}. Find a basis for U(prep)
    (x,y,z) \in U^{\perp} if and only if (x,y,z) \cdot (1,1,0)=(x,y,z) \cdot (0,1,1)=0. that will give you: x+y=y+z=0. thus: x=z=-y and y can be anything. so \{(-1,1,-1) \} is a beasis for U^{\perp}. \ \Box
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