I have . With integer coefficients. I know that and are odd numbers. I have to prove that has no roots over . /// From the fact that is odd I know that is odd... Which approach should I use to finish the proof?
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Hello andreas Just a question : is it or
Originally Posted by running-gag Hello andreas Just a question : is it or It is
Originally Posted by andreas It is OK Suppose is a root of f (with p and q integers and fraction in its lowest terms) Then Multiplying by q^n q dividing the first member divides the second one (p^n) q and p having no common factor then q=1
See this and look at last post.
could you fix the link?
Originally Posted by andreas I have . With integer coefficients. I know that and are odd numbers. I have to prove that has no roots over . if has a rational root, it has to be an integer because is monic. suppose for some now has to be odd since on the other hand for some thus which is impossible because is odd and is even.
Last edited by NonCommAlg; Nov 29th 2008 at 11:30 PM.
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