# Thread: inverse of a jacobian matrix

1. ## inverse of a jacobian matrix

What are the steps in finding the inverse of this matrix?
$\displaystyle 3 z^{(k-1)}\hspace{25 mm} siny^{(k-1)}z^{(k-1)}\hspace{15 mm} y^{(k-1)} sin y^{(k-1)}z^{(k-1)}$
$\displaystyle 2x^{(k-1)}\hspace{24 mm} -162(y^{(k-1)}+0.1) \hspace{13 mm}cos z^{(k-1)}$
$\displaystyle -y^{(k-1)}e^{-x^{(k-1)}y^{(k-1)}} \hspace{5 mm}-x^{(k-1)}e^{-x^{(k-1)}y^{(k-1)}} \hspace{13 mm}20$

$\displaystyle 3 z^{(k-1)}\hspace{25 mm} siny^{(k-1)}z^{(k-1)}\hspace{15 mm} y^{(k-1)} sin y^{(k-1)}z^{(k-1)}$
$\displaystyle 2x^{(k-1)}\hspace{24 mm} -162(y^{(k-1)}+0.1) \hspace{13 mm}cos z^{(k-1)}$
$\displaystyle -y^{(k-1)}e^{-x^{(k-1)}y^{(k-1)}} \hspace{5 mm}-x^{(k-1)}e^{-x^{(k-1)}y^{(k-1)}} \hspace{13 mm}20$