[Hungerford, p99 Q5]
Show that there is a nonabelian subgroup T of $\displaystyle S_3 \times Z_4$ of order 12 generated by elements a,b such that $\displaystyle |a|=6, a^{3}=b^{2},ba=a^{-1}b$.
[Hungerford, p99 Q5]
Show that there is a nonabelian subgroup T of $\displaystyle S_3 \times Z_4$ of order 12 generated by elements a,b such that $\displaystyle |a|=6, a^{3}=b^{2},ba=a^{-1}b$.