[Hungerford, p99 Q5]

Show that there is a nonabelian subgroup T of $\displaystyle S_3 \times Z_4$ of order 12 generated by elements a,b such that $\displaystyle |a|=6, a^{3}=b^{2},ba=a^{-1}b$.

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- Nov 18th 2008, 07:40 PMaliceinwonderlandNonabelian group of order 12
[Hungerford, p99 Q5]

Show that there is a nonabelian subgroup T of $\displaystyle S_3 \times Z_4$ of order 12 generated by elements a,b such that $\displaystyle |a|=6, a^{3}=b^{2},ba=a^{-1}b$.