I have a feeling that this question should not be hard but somehow I don't really understand it.. Please help with some detail explanation if you can... (I don't just need an answer but really want to understand it...)

Let f(x,y) = (-x,y)

h(x,y) = (-1/2 -sqrt3/2) (x)

(sqrt3/2 -1/2 ) (y)

(i.e. rotate counterclockwise and angle of 2pi/3

Define a group G = {f^k.h^j|k = 0,1 ; j = 0,1,2}

Find a formula that expresses (f^i.h^j)*(f^s.h^t) = f^a.h^b

Show that G is nonabelian with order 6

Thank you so much!!!