• Nov 16th 2008, 09:51 PM
My Little Pony

1) Let A be a 3x3 matrix with determinant -12.

2) Let A be a 2x2 matrix such that adj(A) =

[8, -1]
[-5, -4]

What is det(A)?
• Nov 16th 2008, 10:06 PM
o_O
It can be shown that: $\text{det} \left(\text{adj}(A)\right) = \left[\text{det} (A) \right]^{n-1}$

So for #1, just use this directly and simplify using your properties of determinants:
(a): $\text{det} \left(\text{adj}(A^T)\right) = \left[\det(A^T)\right]^{n-1} = \cdots$

(b): $\text{det} \left(\text{adj}(A^{-1})\right) = \left[\det(A^{-1})\right]^{n-1}= \cdots$

(c): $\text{det} \left(\text{adj}(3A)\right) = \left[\det(3A)\right]^{n-1}= \cdots$

For #2, modifying the property I gave you earlier, we get: $\det (A) = \sqrt[n-1]{\det \left(\text{adj} (A)\right)}$

So find the determinant of your adjoint matrix and then take its (n-1)-th root.