Please show that x^3-2 is irreducible in Z/19Z [x]/<x^2-2>. There HAS to be a better way than plugging and chugging 361 polynomials.

Thanks!

Julian

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- Nov 9th 2008, 08:20 PMaznmavenShow that x^3-2 is irreducible in Z/19Z [x]/<x^2-2>
Please show that x^3-2 is irreducible in Z/19Z [x]/<x^2-2>. There HAS to be a better way than plugging and chugging 361 polynomials.

Thanks!

Julian - Nov 11th 2008, 02:17 PMThePerfectHacker