Solve by graphing. If the solutions are not exact, estimate the answers by indicating the consecutive integers between which the roots are located.

x^2-4x+3=0

The answer I got is 2.

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- July 17th 2005, 01:13 PMHayabusagraphing
Solve by graphing. If the solutions are not exact, estimate the answers by indicating the consecutive integers between which the roots are located.

x^2-4x+3=0

The answer I got is 2. - July 17th 2005, 03:35 PMMath Help
x^2-4x+3=0

try plugging in 2 for x and you will see that it does not work:

(2^2)-(4*2)+3=0

4-8+3=0

-1=0 see?

I have attached a graph, where it is evident that the answers are

x = 1 and x = 3

It is difficult to see on the one I have attached but graph it yourself and trace the line and you will see. Remember always check your answers by plugging them back into the equation. - July 17th 2005, 05:36 PMHayabusa
Thank you. I understand the problem now and how you ended up getting 3 and 1.