Find the smallest interior angle of the triangle ABC whose vertices are given:-
A = (3,1,-2) B = (3,0,-1) C = (5,2,-1)
I am not sure what to do here...i tried using the dot product but it didnt workout...any help??
Find vector equations that represent the line segments that connect the three points. Then find the angle between them using the formula:
$\displaystyle \cos\vartheta=\frac{\bold u\cdot\bold v}{||\bold u|| ||\bold v||}\implies\vartheta=\cos^{-1}\left(\frac{\bold u\cdot\bold v}{||\bold u|| ||\bold v||}\right)$
--Chris