Let A and B rings, M a B-module and a ring morphism. Prove that the action defines a structure of A-module over M. thanks!!
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Originally Posted by roporte Let A and B rings, M a B-module and a ring morphism. Prove that the action defines a structure of A-module over M. thanks!! the action is clearly well-defined because if a = a' and x = x', then now M is a B-module and is a homomorphism. therefore: similarly: finally:
Last edited by NonCommAlg; Nov 18th 2008 at 09:11 AM.
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