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Math Help - rose in R^2

  1. #1
    Junior Member
    Joined
    Sep 2008
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    rose in R^2

    The curve in \mathbb{R}^2 given by r = sen(2\theta). Prove that is constructed exactly by the roots of the polynomial

    (X^2+Y^2)^3 - 4X^2Y^2

    thanks!
    Last edited by roporte; November 9th 2008 at 02:49 PM. Reason: great mistake
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