Hi,

I would like to know if I'm doing this right or wrong please help.

For y=-2x^2, write the equation of the axis of symmetry and name the vertex.

My answer:

y=-2x^2

a=(-2) , b= 0 , c= 0

y=(-2)(0) = 0

Then:

x = b/2a

x= 0/2*(-2) = (-0/4)

So y= 0; (0,0)