
Is this right?
Hi,
I would like to know if I'm doing this right or wrong please help.
For y=2x^2, write the equation of the axis of symmetry and name the vertex.
My answer:
y=2x^2
a=(2) , b= 0 , c= 0
y=(2)(0) = 0
Then:
x = b/2a
x= 0/2*(2) = (0/4)
So y= 0; (0,0)

Half of the answer is wrong.
Vertex is (0,0), allright.
But, axis of symmetry is not y = 0.
Axis of symmetry is x = 0, or the yaxis.
y = 2x^2
It is the x that is squared, so a vertical parabola, so a vertical axis of symmetry, so x=0 or the yaxis.

I'm sorry but I do not understand what you are telling me.

Which part you don't understand? All?

This is where you lost me.
But, axis of symmetry is not y = 0.
Axis of symmetry is x = 0, or the yaxis.
y = 2x^2
It is the x that is squared, so a vertical parabola, so a vertical axis of symmetry, so x=0 or the yaxis

I see.
So I assume you don't know parabolas yet.
Funny you were told to look for the axis of symmetry of y = 2x^2, which is a vertical parabola that opens down, whose xvertex is at (0,0).
I don't know how to proceed now.
Wait, do you know, or can you graph y = 2x^2?
If you can, do it. And you will see that the graph is symetrical about the yaxis. The yaxis is vertical. The yaxis is also the x=0 vertical line.