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Math Help - show mapping is automorphism of G

  1. #1
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    show mapping is automorphism of G

    Let G be a group. Show that the mapping phi_a: g-> aga^-1, where a,g are members of G is an automorphism of G. (Inner Automorphism Induced by a)
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    Quote Originally Posted by mandy123 View Post
    Let G be a group. Show that the mapping phi_a: g-> aga^-1, where a,g are members of G is an automorphism of G. (Inner Automorphism Induced by a)
    Just post what you did. This should be a straightforward problem if you go in steps. Step one is to know \phi is homomorphism. Step two is to show \phi is one-to-one. Step three is to show \phi is onto.
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