Let A be a 4 X 2 matrix, A = $\displaystyle \begin{bmatrix}-1&0 \\ 0 & 1 \\ 1&2\\ 2&1 \end{bmatrix}$
Is there a 2X4 matrix such that $\displaystyle BA = I_2$?
A little clarifications would be nice, totally dont understand this question at all.
Let A be a 4 X 2 matrix, A = $\displaystyle \begin{bmatrix}-1&0 \\ 0 & 1 \\ 1&2\\ 2&1 \end{bmatrix}$
Is there a 2X4 matrix such that $\displaystyle BA = I_2$?
A little clarifications would be nice, totally dont understand this question at all.
Yes, I did misunderstand the question.
One way to do it would be to assume that $\displaystyle B = \begin{bmatrix} a& b & c & d \\ e &f & g &h \end{bmatrix}$, do the multiplication, equate entries and solve the resulting four linear equations (infinite number of solutions).