Matrix Inverses, help plz

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October 19th 2008, 07:39 PM
p00ndawg

Matrix Inverses, help plz

Let A be a 4 X 2 matrix, A = $\begin{bmatrix}-1&0 \\ 0 & 1 \\ 1&2\\ 2&1 \end{bmatrix}$

Is there a 2X4 matrix such that $BA = I_2$ ?

A little clarifications would be nice, totally dont understand this question at all.
October 19th 2008, 08:00 PM
mr fantastic

Quote:

Originally Posted by p00ndawg

Let A be a 4 X 2 matrix, A = $\begin{bmatrix}-1&0 \\ 0 & 1 \\ 1&2\\ 2&1 \end{bmatrix}$

Is there a 2X4 matrix such that $BA = I_2$ ?

A little clarifications would be nice, totally dont understand this question at all.

A necessary (but not sufficient) condition for the inverse of a matrix to exist is that the matrix must be square ....
October 20th 2008, 12:55 AM
SimonM

Quote:

Originally Posted by mr fantastic

A necessary (but not sufficient) condition for the inverse of a matrix to exist is that the matrix must be square ....

I think you misunderstood the question. There is a matrix which satisfies

The question is asking can we find a matrix which satisfies the equation and we can

$B = \begin{bmatrix} 1& -1 & 0 & 1 \\ 0 &1 & 0 &0 \end{bmatrix}$ is one example
October 20th 2008, 01:23 AM
mr fantastic

Quote:

Originally Posted by SimonM

I think you misunderstood the question. There is a matrix which satisfies

The question is asking can we find a matrix which satisfies the equation and we can

$B = \begin{bmatrix} 1& -1 & 0 & 1 \\ 0 &1 & 0 &0 \end{bmatrix}$ is one example

So what's $I_2$ meant to represent?
October 20th 2008, 01:29 AM
bumcheekcity

Quote:

Originally Posted by mr fantastic

So what's $I_2$ meant to represent?

$I_2 = \left(\begin{array}{cc}1&0\\0&1\end{array}\right)$

More generally, $I_n$ is the nxn square matrices with 1 in its leading diagonal (i.e. from top-left to bottom-right).
October 20th 2008, 01:39 AM
mr fantastic

Quote:

Originally Posted by SimonM

I think you misunderstood the question. There is a matrix which satisfies

The question is asking can we find a matrix which satisfies the equation and we can

$B = \begin{bmatrix} 1& -1 & 0 & 1 \\ 0 &1 & 0 &0 \end{bmatrix}$ is one example

Yes, I did misunderstand the question.

One way to do it would be to assume that $B = \begin{bmatrix} a& b & c & d \\ e &f & g &h \end{bmatrix}$ , do the multiplication, equate entries and solve the resulting four linear equations (infinite number of solutions).
October 20th 2008, 01:40 AM
SimonM

Quote:

Originally Posted by mr fantastic

Yes, I did misunderstand the question.

One way to do it would be to assume that $B = \begin{bmatrix} a& b & c & d \\ e &f & g &h \end{bmatrix}$ , do the multiplication, equate entries and solve the resulting four linear equations (infinite number of solutions).

That is indeed how I did it (same letters and everything!)
October 20th 2008, 01:45 AM
mr fantastic

Quote:

Originally Posted by SimonM

That is indeed how I did it (same letters and everything!)

Well you know what they say about great minds ......
October 20th 2008, 01:46 AM
SimonM

Quote:

Originally Posted by mr fantastic

Well you know what they say about great minds ......

... and fools
October 20th 2008, 03:51 AM
CaptainBlack

Quote:

Originally Posted by p00ndawg

Let A be a 4 X 2 matrix, A = $\begin{bmatrix}-1&0 \\ 0 & 1 \\ 1&2\\ 2&1 \end{bmatrix}$

Is there a 2X4 matrix such that $BA = I_2$ ?

A little clarifications would be nice, totally dont understand this question at all.

By inspection one such matrix is:

$<br /> \begin{bmatrix}-1&0 &0&0\\ 0&1&0&0 \end{bmatrix}<br />$

CB
October 20th 2008, 05:52 AM
p00ndawg

ahhh I see thank you guys.