I really need help.

How do you do this problem?

Factor 4g from: 8g^2j - 12g^3hj :confused:

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- Jul 6th 2005, 06:35 PMHayabusaneed help
I really need help.

How do you do this problem?

Factor 4g from: 8g^2j - 12g^3hj :confused: - Jul 6th 2005, 07:50 PMMath HelpFactor question
Factor 4g from: 8g^2j - 12g^2hj

Do you mean?: $\displaystyle 8g^{2j} - 12g^{2hj}$ - Jul 7th 2005, 12:13 PMHayabusa
I wrote it the way the book shows the problem.

Factor 4g from: 8g^2 j - 12g^3 hj

I'm really confused I've looked in the book and I can not find an example of this problem anywhere. - Jul 7th 2005, 03:52 PMMathMan
i think what you mean is:

$\displaystyle 8g^2j - 12g^3hj $

If that is the case then it is pretty easy to factor out a 4g.

You would get:

$\displaystyle 2gj - 3g^2hj$

You simply divide by 4g. - Jul 7th 2005, 04:29 PMHayabusa
Thanks for the help.

- Jul 7th 2005, 05:10 PMMathGuruFactoring out
Just to be more precise:

$\displaystyle 8g^2j - 12g^3hj$

to factor out 4g you would write the following:

$\displaystyle 4g[2gj - 3g^2hj]$

- Jul 7th 2005, 05:14 PMHayabusa
Thank you all once again for the help.