# full-rank matrix problem

• Oct 12th 2008, 06:08 AM
marianne
full-rank matrix problem
I'm having trouble understanding one part of the proof I'm studying.

The matrix $\left[ \begin{array}{ccc} a & b & c \\ d & e & f \end{array} \right]$ is full-rank.
Now we suppose that this
$\left[ \begin{array}{cc} a & b \\ d & e \end{array} \right]$
is the full-rank part.

Why can we do this?

Thank you for your help, this is really confusing me.
• Oct 12th 2008, 11:09 AM
Prometheus
saying that the matrix has full rank means that it is of rank 2 - so there are two columns which are independent. you don't really know which 2, but for most proofs it doesn't matter. so you say without loss of generality, the first two columns are independent and therefore $\left[ \begin{array}{cc} a & b \\ d & e \end{array} \right]$ is of rank 2. the proof would probably work as well for the 1st and 3rd columns if they are independent too, etc.

by the way, you might have a 2x3 matrix that every two columns are independent, yet it must be of rank 2, for example
$\left[ \begin{array}{ccc} 1 & 0 & 1 \\ 0 & 1 & 1 \end{array} \right]$
• Oct 13th 2008, 10:59 AM
marianne
Thank you!