Solve the given system of equations using either Gaussian or Gauss-Jordan elimination.

a)2w+3x-y+4z=0

3w-x+z=1

3w-4x+y-z=2

b) -w+3x-2y+4z=0

2w-6x+y-2z=-3

w-3x+4y-8z=2

Printable View

- October 10th 2008, 10:16 AMYanSystems of Linear Equations
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination.

a)2w+3x-y+4z=0

3w-x+z=1

3w-4x+y-z=2

b) -w+3x-2y+4z=0

2w-6x+y-2z=-3

w-3x+4y-8z=2 - October 10th 2008, 05:11 PMwatchmath
In my opinion people won't response your question. The main reason is that it is messy to right matrix in latex. The second one elimination problem is kind of routine so no body has no interest to answer.

Show us how much you have done with this problem and we (should I say I) will be happy to assist you. (Rofl) - October 10th 2008, 06:52 PMChris L T521
I will only do one, since these will take a while... (Nod)

--------------------------------

--------------------------------

--------------------------------

--------------------------------

--------------------------------

--------------------------------

We have 3 equations with 4 unknowns. Let us introduce a parameter, say

Using Gaussian Elimination, we can now back substitute:

Therefore, the solution set is

(Whew)

Does this make sense?

--Chris - October 10th 2008, 07:02 PMChris L T521
That is a possibility...but there is a neat way of creating matrices without using

Code:`\left[\begin{array}{cccc} [insert matrix here] \end{array}\right]`

Code:`\begin{bmatrix} [insert matrix entries here] \end{bmatrix}`

For example, instead of using

Code:`\left[\begin{array}{cccc} 1&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1 \end{array}\right]`

Code:`\begin{bmatrix}1&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1 \end{bmatrix`

Quote:

The second one elimination problem is kind of routine so no body has no interest to answer.

--Chris