Write an equation in slop-intercet form for the line through points (2,4) and (6,-2).
What I did was:
-2 - 4 -6 3
------ = ---- = ---
6 - 2 4 2
Then
y - 4 = -3/2(x-2)
y - 4 = -3/2x - 2
answer
y = -3/2x + 2
Is this right? :confused:
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Write an equation in slop-intercet form for the line through points (2,4) and (6,-2).
What I did was:
-2 - 4 -6 3
------ = ---- = ---
6 - 2 4 2
Then
y - 4 = -3/2(x-2)
y - 4 = -3/2x - 2
answer
y = -3/2x + 2
Is this right? :confused:
You are correct up to the line
y - 4 = (-3/2)(x-2)
The continuation should be like this
y -4 = -(3/2)x -2(-3/2)
y -4 = -(3/2)x +3
y = -(3/2)x +3 +4
y = -(3/2)x +7 ----answer.
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If the answer were
y = -(3/2)x + 2,
would points (2,4) and (6,-2) be in that line?
thank you.