Write an equation in slop-intercet form for the line through points (2,4) and (6,-2).

What I did was:

-2 - 4 -6 3

------ = ---- = ---

6 - 2 4 2

Then

y - 4 = -3/2(x-2)

y - 4 = -3/2x - 2

answer

y = -3/2x + 2

Is this right? :confused:

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- Jul 3rd 2005, 05:22 PMHayabusaIs this right or wrong?
Write an equation in slop-intercet form for the line through points (2,4) and (6,-2).

What I did was:

-2 - 4 -6 3

------ = ---- = ---

6 - 2 4 2

Then

y - 4 = -3/2(x-2)

y - 4 = -3/2x - 2

answer

y = -3/2x + 2

Is this right? :confused: - Jul 3rd 2005, 06:14 PMticbol
You are correct up to the line

y - 4 = (-3/2)(x-2)

The continuation should be like this

y -4 = -(3/2)x -2(-3/2)

y -4 = -(3/2)x +3

y = -(3/2)x +3 +4

y = -(3/2)x +7 ----answer.

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If the answer were

y = -(3/2)x + 2,

would points (2,4) and (6,-2) be in that line? - Jul 3rd 2005, 06:20 PMHayabusa
thank you.