Let H= {phi element of Sn | phi(n)=n} What's the index of H in Sn? the index of H in Sn = |Sn|/|H| and I know |Sn|= n! I was told the order of H is (n-1)! but i don't see how Could anyone help?
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Originally Posted by frankdent1 Let H= {phi element of Sn | phi(n)=n} What's the index of H in Sn? the index of H in Sn = |Sn|/|H| and I know |Sn|= n! I was told the order of H is (n-1)! but i don't see how Could anyone help? Basically are all permutations that fix . Therefore can be regarded as the group of all permutations of i.e. isomorphic to and so .
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