(xy)^(-1) = b^(-1)a^(-1), keeping in mind the group may not be commutative. Thanks.
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Originally Posted by universalsandbox (xy)^(-1) = b^(-1)a^(-1), keeping in mind the group may not be commutative. Thanks. To show you need to show . Can you do that now?
Originally Posted by ThePerfectHacker To show you need to show . Can you do that now? Could you add a little more process to that please? This stuff is very new to me. Thanks.
Originally Posted by universalsandbox Could you add a little more process to that please? This stuff is very new to me. Thanks. Say that . What does that mean? It means that and . That is the definition of what it means to be a multiplicative inverse. In your problem you have and .
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