Hi again

Just after an answer check if that's OK

The eigenvalues of Matrix A are -1,1 and 2. What are the eigenvalues of the Matrix $\displaystyle (2A-3I)^-1$

I have got the eigenvalues of 3I to be 3,3,3 so in the equation and then the inverse gives me $\displaystyle \frac{-1}{5}, -1, 1$

Is this correct?

Thanks