I need help solving this problem.

Determine the x-intercept and y-intercept of the graph of each equatiion:

(15) 2x+4y=8

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- June 22nd 2005, 04:32 PMHayabusaNeed help
I need help solving this problem.

Determine the x-intercept and y-intercept of the graph of each equatiion:

(15) 2x+4y=8 - June 22nd 2005, 05:03 PMMathGuruintercept
Graph the equation and you will understand why

For x intercept (where the graph crosses x-axis) plug in 0 for y.

for y intercept (where the graph crosses y-axis) plug in 0 for x.

Try it in a reply and I will correct you. - June 22nd 2005, 05:18 PMHayabusa
(15)2*0+4*0=8

my answer: 1.875 - June 22nd 2005, 05:32 PMMathGuruintercepts
You need to solve x and y intercept seperately.

First set x = to zero and solve for y:

2*0+4y=8

4y=8

y=2 <---answer for x-intercept

then set y = 0 and solve for x

2x+4*0=8

2x=8

x=4 <---answer for y-intercept

Graph the equation and see if you understand what it is we are solving for. Understand that the equation crosses the x axis when y = 0 and vice versa. - June 23rd 2005, 02:53 PMHayabusa
Thank you.