# Plz Help

• Jun 21st 2005, 02:49 PM
Hayabusa
Plz Help
Write an equation in slope-intercept form of the line passing through each pair of points: (6, -2) and (3, -4)

-4 - (-2)
--------- = -2/3
3 - 6

next

y - (-2) = -2/3(x - 6)
y - (-2) -2/3x -9
y - (-2) + (-2) = -2/3x -9 + (-2)

y= -2/3x + 7 <-- my answer.

Let me now if I'm correct or wrong?
• Jun 22nd 2005, 12:05 AM
ticbol
You tried to find the slope of the line.
Then you used that slope in the point-slope form of the equation of the line.

Mistakes in the Algebra. I'd say, mistakes due to skipping steps.

-4 - (-2)
--------- = -2/3
3 - 6

Maybe if you did not skip one step you could have got the correct slope.
Like this:
-4 - (-2)
--------- = -2/(-3) = 2/3 <---the correct slope is positive.
3 - 6

next

y - (-2) = (2/3)(x - 6)
y - (-2) = (2/3)x -(2/3)6
y - (-2) = (2/3)x -4
y -(-2) +(-2) = (2/3)x -4 +(-2)

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Of course it is okay to skip steps. But if you are not that good yet, maybe it's good for you to do it step by step.

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