Thread: Urgent Help

Hey guys can you please help me with these two problems? I just do not understand how to do them, I don't know where to begin!



Find each value if g(x) = 2x + 3 and h(x) = x/2-7


Find: G(9)

Find: H(4)

This type of problem is an exercise in substituting a value (such as 9) for a variable (such as x).

1. Find: G(9) if G(x) = 2x + 3

we replace x with 9 in the above equation so:

G(9) = 2*9+3 .........|replace x with 9
G(9) = 18+3 ...........|multiplacation before addition (PEMDAS)
G(9) = 21

Try to do the second one here as a reply and I will correct you.

So for problem: H(4)


H(4)= 4/2-7

4/-5

= -0.8

Please correct me if I am wrong.

h(x) = x/2-7
Find: H(4)

Don't forget the order of operations. First you devide then you subtract. So you have:

Thank you for your help. I appreciate it very much

Regarding order of operations:

Remember PEMDAS

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

So if there are no parentheses as in the above problems, you first do exponents then multiplication then division etc.