Eigenvectors

I've calculated the following eigen value and determined the following matrix:

eigenvalue, U= -5


Original matrix
([-5-U] 2 -3)
(0 [1-U] -2)
(0 1 [4-U])

Solved Matrix:

(0 0 28)0
(0 3 -1)0
(0 0 0) 0

I'm not exactly clear on how to determined the eigenvector

Quote:

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Originally Posted by jschlarb

I've calculated the following eigen value and determined the following matrix:

eigenvalue, U= -5


Original matrix
([-5-U] 2 -3)
(0 [1-U] -2)
(0 1 [4-U])

Solved Matrix:

(0 0 28)0
(0 3 -1)0
(0 0 0) 0

I'm not exactly clear on how to determined the eigenvector

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Solve MX = -5X for X, where M is the given matrix and X = [x, y, z]^T is the eigen vector.

You should get x = t, y = z = 0. So the eigenvector corresponding to the eigenvalue u = -5 is [1, 0, 0]^T.

Quote:

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Originally Posted by mr fantastic

Solve MX = -5X for X, where M is the given matrix and X = [x, y, z]^T is the eigen vector.

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I should have added that there are two other eigenvalues: u = 2 and u = 3 ......