Help please!

**luckyc1423** · July 23rd 2006, 11:26 AM

Let W be the subspace of R^4 spanned by :
[ 2
0
-1
3]
and
[ -6
1
5
-8]
Find a basis for W^(upside down T)

dont know the correct word for the symbol that looks like an Upside down T

**CaptainBlack** · July 24th 2006, 01:27 AM

Originally Posted by luckyc1423

Let W be the subspace of R^4 spanned by :
[ 2, 0, -1, 3]' and [-6, 1, 5, -8]'

Find a basis for W^(upside down T)

dont know the correct word for the symbol that looks like an Upside down T

$\{[1,\ 0,\ 0,\ 0]',\ [0,\ 1,\ 0,\ 0]',$ $\ [ 2,\ 0,\ -1,\ 3]',\ [-6,\ 1,\ 5,\ -8]'\}=\{e_1,e_2,w_1,w_2\}$

is a basis of $\mathbb{R}^4$ (proof left as an excercise for the reader).

Now $w_1,\ w_2$ is a basis for $W$ , so $[w_1,w'_2]$ ,
where:

$ w'_2=w_2-\frac{\langle w_1,w_2\rangle w_1}{\|w_1\|^2} $

is an orthogonal basis for $W$ .

Now let:

$ e'_1=e_1-\frac{\langle e_1,w_1\rangle w_1}{\|w_1\|^2}-\frac{\langle e_1,w'_2\rangle w'_2}{\|w'_2\|^2} $

and:

$ e'_2=e_2-\frac{\langle e_2,w_1\rangle w_1}{\|w_1\|^2}-\frac{\langle e_2,w'_2\rangle w'_2}{\|w'_2\|^2}}-\frac{\langle e_2,e'_1\rangle e'_1}{\|e'_1\|^2} $ .

Now if I have done this right we should have $\{e'_1,\ e'_2,\ w_1,\ w'_2\}$
is an orthogonal basis of $\mathbb{R}^4$ , with $\{w_1,\ w'_2\}$ an orthogonal basis
of $W$ , and $\{e'_1,\ e'_2\}$ and orthogonal basis of $W^{\bot}$ .

RonL

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