Show that

$\displaystyle \begin{pmatrix} 4\\0\\1 \end{pmatrix}$ , $\displaystyle \begin{pmatrix} 2\\1\\0 \end{pmatrix}$

and

$\displaystyle \begin{pmatrix} 2\\-1\\1 \end{pmatrix}$ , $\displaystyle \begin{pmatrix} 0\\2\\-1 \end{pmatrix}$

are two different bases for the plane

$\displaystyle x-2y-4z=0$

Thanks in advance!