Originally Posted by adrian1116 on a different postYou should never ask the same question twice Adrian...Originally Posted by adrian1116
Since TPH closed the other thread, there is no place else to answer this question.
Hi, Adrian. How much do you know about this stuff? I'm experimenting here to see if it is possible to explain this in a short space.Originally Posted by adrian1116
Here is your example worked out.
Set up this tableau. Do you see how the tableau relates to your problem? We start off with the slack variables equal to the constant terms in the equations (for example ) and
Do you know what it means to pivot? It means to reduce a column using row operations to zeroes in every row but one row that has a 1 in it. You apply those same row operations to all the other columns.
To get the next tableau, pivot using the row and column with the box. This means we are bringing variable into the solution replacing variable
The next tableau is the result of the first pivoting. Keep track in the first column of what row and column was used to pivot.
To get to the next tableau, pivot using the row and column with the box. This means we are bringing variable into the solution replacing variable
The next tableau is the result of the second pivoting. Again, keep track in the first column of what row and column was used to pivot.
This is a solution to the equations: It's a solution because variables are in as desired. There were no constraints on the slack variables so turns out negative.
Well Adrian, did this make any sense at all to you?