I got the following matrix:
-1 3 2 -8
1 0 1 -2
3 3 a b
Then i applied R2=R2+R1 AND R3=R3+3R1 which gives
-1 3 2 -8
0 3 3 -6
0 12 a+6 b-24
But now am stuck, how do i get a 0 in the position of 12?
Thanks
You can paramterize the soutuions as follows
let
Then the equation above the row of zero's is
and using these we can solve for x
So finally we get the solution
This can be broken up into the particular and complimentry solution
where
This is true for any
Note that spans the null space of the homogenious system