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Evales x + y + z = 4
2x + 3y + z = 8
3x + (3-p)y + 2z = 13-(p^2)
I've reduced the system of equations to:
x + y + z = 4
y - z = 0
(p+1)y = (p^2) - 1
It then says:
"For each of p = 1 and p = -1 indicate how many solutions there are to the system of equations. I there is a unique solution, give that solution. If there are infinitely many solutions give the resulting unique solution when
(i) z = 1
(ii) z = -1
I've found that p=1 give unique and p = -1 give infinite.
PS. My elimination is fine I have the answers.
(i) z = 1, y = 1, x = 6
(ii) z = -1, y = -1, x = 6
I just don't know how to solve if it is infinite.