I am having trouble with this question:
Determine the slope and the y-intercept from the equation below, then graph the line:
y=-(3/2)x +2
y=-(3/2)x +2
To determine the slope:
This equation describes a line in the form of y=mx+b where m is the slope of the line and b is the y-intercept.
So m = -(3/2) <- this is the slope of the line
To determine the y-intercept:
b=2 <- this is the y-intercept
To graph the line in a graphing calculator such as a TI press 'Y=' then enter your equation just as you've written it. Then press the graph button and make sure that your zoom window is an appropriate size (zoom normal is fine). You should see a line that crosses the y axis at y=2 and crosses the x axis at x=(4/3).
I hope this helps, please don't hesitate to ask for any clarifications.
Math Guru