I am having trouble with this question:

Determine the slope and the y-intercept from the equation below, then graph the line:

y=-(3/2)x +2

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- Mar 28th 2005, 08:17 PMpinky&thebrainSlope & Y-Intercept
I am having trouble with this question:

Determine the slope and the y-intercept from the equation below, then graph the line:

y=-(3/2)x +2 - Mar 28th 2005, 10:10 PMMathGuruy=mx+b determining slope and y-intercept
y=-(3/2)x +2

To determine the slope:

This equation describes a line in the form of y=mx+b where m is the slope of the line and b is the y-intercept.

So m = -(3/2) <- this is the slope of the line

To determine the y-intercept:

b=2 <- this is the y-intercept

To graph the line in a graphing calculator such as a TI press 'Y=' then enter your equation just as you've written it. Then press the graph button and make sure that your zoom window is an appropriate size (zoom normal is fine). You should see a line that crosses the y axis at y=2 and crosses the x axis at x=(4/3).

I hope this helps, please don't hesitate to ask for any clarifications.

Math Guru