A difficult problem for me.

let ( ) = A so that and . Prove that det A > 0

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- May 18th 2008, 02:38 PMkezmanDeterminant
A difficult problem for me.

let ( ) = A so that and . Prove that det A > 0 - May 18th 2008, 03:55 PMKGene
- May 18th 2008, 04:08 PMkezman
Sorry I forgot:

the first condition is for

the second condition is for all - May 19th 2008, 12:21 AMKGene
- May 19th 2008, 02:20 AMOpalg
Such a matrix is called diagonally dominant. The result that you want follows from the Gershgorin circle theorem.