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Math Help - simplifying this equation

  1. #1
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    simplifying this equation

    how does this:

    (3 - &)(2-&)(4-&) - 2(8-2&)-2(4-2&)= 0

    where & is equal to lambada(sorry cant seem to get symbol on)

    end up as this:

    &^3 - 9&^2 + 18& = 0

    cheers
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by thermalwarrior View Post
    how does this:

    (3 - &)(2-&)(4-&) - 2(8-2&)-2(4-2&)= 0

    where & is equal to lambada(sorry cant seem to get symbol on)

    end up as this:

    &^3 - 9&^2 + 18& = 0

    cheers
    Small wonder that you are having troubles: It doesn't.

    Your expression comes out as -\lambda ^3 + \lambda ^2 + 22 \lambda - 40

    -Dan
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  3. #3
    Moo
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    Hello,

    Quote Originally Posted by topsquark View Post
    Small wonder that you are having troubles: It doesn't.

    Your expression comes out as -\lambda ^3 + \lambda ^2 + 22 \lambda - 40

    -Dan
    I find it to be -\lambda^3+9 \lambda^2-18 \lambda=0, simply by developping

    This equation is the one given (divide by -1).
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