how does this:

(3 - &)(2-&)(4-&) - 2(8-2&)-2(4-2&)= 0

where & is equal to lambada(sorry cant seem to get symbol on)

end up as this:

&^3 - 9&^2 + 18& = 0

cheers

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- May 6th 2008, 09:58 AMthermalwarriorsimplifying this equation
how does this:

(3 - &)(2-&)(4-&) - 2(8-2&)-2(4-2&)= 0

where & is equal to lambada(sorry cant seem to get symbol on)

end up as this:

&^3 - 9&^2 + 18& = 0

cheers - May 6th 2008, 02:01 PMtopsquark
- May 6th 2008, 02:42 PMMoo