if you have 3 vectors: them being (x,1,3) (0,1,2) (x,1,x) how do you find the values of x to which you cant form a base of R^3. doesn't even make sense at least i dont think it does.
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The determinate cannot be zero. $\displaystyle \left| {\begin{array}{ccc} x & 1 & 3 \\ 0 & 1 & 2 \\ x & 1 & x \\ \end{array}} \right| = x^2 - 3x$ What values of x gives a determinate of zero?
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