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  1. #1
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    vectors

    if you have 3 vectors: them being (x,1,3)
    (0,1,2)
    (x,1,x)

    how do you find the values of x to which you cant form a base of R^3.

    doesn't even make sense at least i dont think it does.
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  2. #2
    MHF Contributor

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    The determinate cannot be zero.
    \left| {\begin{array}{ccc}   x & 1 & 3  \\   0 & 1 & 2  \\   x & 1 & x  \\<br />
\end{array}} \right| = x^2  - 3x
    What values of x gives a determinate of zero?
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