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Thread: vectors

  1. May 5th 2008, 03:38 PM #1
    ingowah33
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    vectors

    if you have 3 vectors: them being (x,1,3)
    (0,1,2)
    (x,1,x)

    how do you find the values of x to which you cant form a base of R^3.

    doesn't even make sense at least i dont think it does.
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  2. May 5th 2008, 03:51 PM #2
    Plato
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    The determinate cannot be zero.
    \left| {\begin{array}{ccc} x & 1 & 3 \\ 0 & 1 & 2 \\ x & 1 & x \\<br /> \end{array}} \right| = x^2 - 3x
    What values of x gives a determinate of zero?
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