Use an orthogonal transformation and a translation to express in standard form the curve given by the equation http://www.cramster.com/Answer-Board...1412501988.gif

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- May 5th 2008, 07:36 AMmatty888Express curve in standard form
Use an orthogonal transformation and a translation to express in standard form the curve given by the equation http://www.cramster.com/Answer-Board...1412501988.gif

- May 5th 2008, 07:46 AMtopsquark
You will want to rotate the axes here.

$\displaystyle x = x'~cos(\theta) - y'~sin(\theta)$

$\displaystyle y = x'~sin(\theta) + y'~cos(\theta)$

Then you want to pick a value for $\displaystyle \theta$ such that the x'y' term has a coefficient of 0. Then its just a matter of completing the square on x' and y'.

-Dan