Suppose h12->z/12z is a homomorphism of groups.Prove that g(t^2)=[0] mod 12 My attempt so far is g(t6) = [0]9 by Homomorphism g(a*b)=g(a) * g(b) g(t^2*t^2*t^2) = g(t2) *g(t2)*g(t2) g(t6) 0 = 3g(t2)
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