Prove that Q[sqrt(2)] is closed under addition, and show that MIV Holds. Q[Sqrt(2)] is define by a+bsqrt(2), a and b in Q. MIV is existence of multiplicative inverse Ex: aa^-1=1
Last edited by JCIR; April 25th 2008 at 05:06 PM.
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Originally Posted by JCIR Prove that Q[sqrt(2)] is closed under addition, and show that MIV Holds. When you post a question why don't you define the terms? I dare say that most of us have no idea what 'MIV' means!
Originally Posted by JCIR Prove that Q[sqrt(2)] is closed under addition, and show that MIV Holds. Q[Sqrt(2)] is define by a+bsqrt(2), a and b in Q. MIV is existence of multiplicative inverse Ex: aa^-1=1 To construct MIV: If , so will and Thus To prove its existence, start with the constructed form and multiply out and show that the product is 1
I suppose showing it is closed under addition is no problem?
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