Thread: Linear independence

v=(6, -3, 0)
u=(-3, 5, -7)
w=(9, 6, k)

what real number can't k be for the vectors to be linearly independent?

Hi

What about calculating the determinant of the three vectors ? When it's null, the vectors are linearly dependent and it'll give you the condition on .

Originally Posted by weasley74

v=(6, -3, 0)
u=(-3, 5, -7)
w=(9, 6, k)

what real number can't k be for the vectors to be linearly independent?

set up the augmented matrix: . equate it to zero and solve the system. the k for which the system only has the trivial solution is linearly independent

I've tried all of this, and I keep getting the wrong answer.

Then write your answers here so that we can correct them.

I get that k can't be 21 for the vectors to be linearly independent, please correct me

Maybe should I have asked for the calculations instead of the answers ? (if you get k=21 check the signs, it might help)

thanks! sign problem. jeez, i've been going crazy over this