v=(6, -3, 0) u=(-3, 5, -7) w=(9, 6, k) what real number can't k be for the vectors to be linearly independent?
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Hi What about calculating the determinant of the three vectors ? When it's null, the vectors are linearly dependent and it'll give you the condition on .
Originally Posted by weasley74 v=(6, -3, 0) u=(-3, 5, -7) w=(9, 6, k) what real number can't k be for the vectors to be linearly independent? set up the augmented matrix: . equate it to zero and solve the system. the k for which the system only has the trivial solution is linearly independent
I've tried all of this, and I keep getting the wrong answer.
Then write your answers here so that we can correct them.
I get that k can't be 21 for the vectors to be linearly independent, please correct me
Maybe should I have asked for the calculations instead of the answers ? (if you get k=21 check the signs, it might help)
thanks! sign problem. jeez, i've been going crazy over this
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