Consider:
Thanks for the help, I kinda get the approach but I don't quite know how to present it. Like, where do I start?
As I know, the way to prove that something is linearly independent or not is through row reduction then compare the ranks. What about this one?
QUOTE=pearlyc;132175]As I know, the way to prove that something is linearly independent or not is through row reduction then compare the ranks. What about this one?[/QUOTE]
You must first learn to general definitions.
If one can find a nontrivial linear combination that equals the zero then the collection is dependent. Row reductions are applied to matrices and not to general spaces.
Is it alright if I were to approach the question like this,
A linear dependent vector is when we have n vectors and one can be expressed as a linear combination of the rest. When this is impossible, we say the vectors are linearly indepedent.
Considering,
a(3sin^2 x) + b(2cos^2 x) = 6
a(3sin^2 x) + b(2cos^2 x) = 6(sin^2 x + cos^2 x)
3asin^2 x + 2bcos^2 x = 6sin^2 x + 6cos^2 x
Comparing coefficients,
3a = 6
Therefore, a = 2
2b = 6
Therefore, b = 3
Since the vectors could be expressed as a linear combination, therefore we can say that the vectors are linearly dependent.
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Do you think this working makes sense and would be acceptable?