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Math Help - MATRIX problem: Help needed

  1. #1
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    MATRIX problem: Help needed

    Hi,

    Pls help to pricved solution of the below problem.

    Consider the following 3 matrices:

    2 12 18
    13 15 20
    19 17 1

    12 2 1
    13 14 21
    9 18 7

    12 2 7
    30 18 22
    9 16 4


    Find --> (inverse of A i.e A-1) x (B x C)

    Please mail me the solution on lalitchugh@yahoo.com


    Best Regards
    Lalit Chugh
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by lalitchugh
    Hi,

    Pls help to pricved solution of the below problem.

    Consider the following 3 matrices:

    2 12 18
    13 15 20
    19 17 1

    12 2 1
    13 14 21
    9 18 7

    12 2 7
    30 18 22
    9 16 4


    Find --> (inverse of A i.e A-1) x (B x C)
    A^{-1} B (-C)\approx \left[ \begin{array}{ccc}<br />
-51.6&-54.6&-32.5\\<br />
16.9&35.7&8.2\\<br />
-17.4&-21.9&-9.2<br />
\end{array} \right]<br />

    Please mail me the solution on lalitchugh@yahoo.com
    No.

    RonL
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by CaptainBlack
    A^{-1} B (-C)\approx \left[ \begin{array}{ccc}<br />
-51.6&-54.6&-32.5\\<br />
16.9&35.7&8.2\\<br />
-17.4&-21.9&-9.2<br />
\end{array} \right]<br />



    No.

    RonL
    Or to be precise:

    \frac{1}{2602} \left [ \begin{array}{ccc}-134355&-142196&-84492\\43995&92792&21298\\-45192&-57048&-23892\end{array} \right ]

    To expand on CaptainBlack's "no," please be aware that it is better for everyone on the site to have the solution posted here so someone else who wants to learn the process can do so and ask questions about it. If the solution is simply sent to your e-mail others will not benefit as well.

    -Dan
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  4. #4
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    Quote Originally Posted by topsquark
    Or to be precise:

    \frac{1}{2602} \left [ \begin{array}{ccc}-134355&-142196&-84492\\43995&92792&21298\\-45192&-57048&-23892\end{array} \right ]

    To expand on CaptainBlack's "no," please be aware that it is better for everyone on the site to have the solution posted here so someone else who wants to learn the process can do so and ask questions about it. If the solution is simply sent to your e-mail others will not benefit as well.

    -Dan
    I was trying to avoid being too helpfull

    RonL
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by CaptainBlack
    I was trying to avoid being too helpfull

    RonL
    Oops!

    -Dan
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  6. #6
    Grand Panjandrum
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    New Question about Gauss-Jordan split out from this thread into a thread of its own here

    RonL
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  7. #7
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    Hello, Lalit!

    Who assigned this hideous problem . . . Torquemada?
    . . (No one expects the Spanish Inquisition!)


    Given: . A = \begin{pmatrix}2&12&18\\13&15&20\\19&17&1\end{pmat  rix}\;\;B = \begin{pmatrix}12&2&1\\13&14&21\\9&18&7\end{pmatri  x}\;\;C = \begin{pmatrix}12&2&7\\30&18&22\\9 &16&4\end{pmatrix}

    Find: . A^{-1} \times B \times (-C)

    Thanks to topsquark's work, all you have to do is:

    . . \frac{1}{2602}\begin{pmatrix}\text{-}134355&\text{-}142196&\text{-}84492\\43995&92792&21298\\\text{-}45192&\text{-}57048&\text{-}23892\end{pmatrix}\,\begin{pmatrix}12&2&1\\13&4&2  1\\9&18&7\end{pmatrix} \begin{pmatrix}\text{-}12&\text{-}2&\text{-}7\\\text{-}30&\text{-}18&\text{-}22\\\text{-}9&\text{-}16&\text{-}4\end{pmatrix}

    Good luck!
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