I am trying to solve for k and i get to the step: 2^n=k^k How do i deal with k raised to itself....its driving me nuts
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that I know of unless you are using the concept of incredibely large numbers....if you are you can say that otherwise I have no idea.
Originally Posted by JesseHackett I am trying to solve for k and i get to the step: 2^n=k^k How do i deal with k raised to itself....its driving me nuts The exact solution is , where W is the Lambert W-function. A search of the MHF will uncover several threads where the Lambert W-function is discussed. where . by definition of the Lambert W-function .
Last edited by mr fantastic; April 5th 2008 at 07:53 PM.
Originally Posted by mr fantastic The exact solution is , where W is the Lambert W-function. A search of the MHF will uncover several threads where the Lambert W-function is discussed. where . by definition of the Lambert W-function . Postscript: An alternative form of this solution is .
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