I found the answer in my book
A^3 is equal to A*A^2 and A^n is equal to [a11^(n-1) a12^(n-1); a21^(n-1) a22^(n-1)] (general form)
Let A = [1/2 -1/2; -1/2 1/2]
Computer A^2 and A^3. What will A^n turn out to be?
I computed A^2, how can I computer A^3? Is it possible to just multiply the product of A^2 with another A? That doesn't seem right to me though. And I have no idea how to find A^n. Thanks for the help!